What are the solutions to the equation (r-1)^2(r+1)^3=0 ?

The solutions to the equation (r-1)^2(r+1)^3=0 are r=1,r=-1

Find the zeros of (r-1)^2(r+1)^3=0

The zeros of (r-1)^2(r+1)^3=0 are r=1,r=-1

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(r - 1)^{2} (r + 1)^{3} = 0

r = 1, r = - 1

Solution steps

(r - 1)^{2} (r + 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 1 = 0 or r + 1 = 0

Solve

r - 1 = 0 : r = 1

Solve

r + 1 = 0 : r = - 1

The solutions are

r = 1, r = - 1

2 x^{3} + x^{2} - 6 x - 7 = 2 x^{2} + 3 x - 7

4 x^{3} = 756

47.24 = 2370.903 (b^{2008})

x^{4} + 9 x^{3} + x^{2} + 9 = 0

x^{3} - 7 x + 10 = 0

What are the solutions to the equation (r-1)^2(r+1)^3=0 ?
The solutions to the equation (r-1)^2(r+1)^3=0 are r=1,r=-1
Find the zeros of (r-1)^2(r+1)^3=0
The zeros of (r-1)^2(r+1)^3=0 are r=1,r=-1