What are the solutions to the equation 1/2 t^2(t^2-2t+1)=0 ?

The solutions to the equation 1/2 t^2(t^2-2t+1)=0 are t=0,t=1

Find the zeros of 1/2 t^2(t^2-2t+1)=0

The zeros of 1/2 t^2(t^2-2t+1)=0 are t=0,t=1

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\frac{1}{2} t^{2} (t^{2} - 2 t + 1) = 0

t = 0, t = 1

Solution steps

\frac{1}{2} t^{2} (t^{2} - 2 t + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or t^{2} - 2 t + 1 = 0

Solve

t^{2} - 2 t + 1 = 0 : t = 1

The solutions are

t = 0, t = 1

x^{3} - 7 x^{2} - 57 x + 15 = 0

s, s^{3} + 12 s^{2} + 20 s = 0

x^{2} - 3 = \frac{x ( x ^{2} - 9 )}{4}

2 b^{8} - 18 b^{6} = 0

(z - 4)^{3} = 0

What are the solutions to the equation 1/2 t^2(t^2-2t+1)=0 ?
The solutions to the equation 1/2 t^2(t^2-2t+1)=0 are t=0,t=1
Find the zeros of 1/2 t^2(t^2-2t+1)=0
The zeros of 1/2 t^2(t^2-2t+1)=0 are t=0,t=1