What are the solutions to the equation x^3-x^2+x+39=0 ?

The solutions to the equation x^3-x^2+x+39=0 are x=-3,x=2+3i,x=2-3i

Find the zeros of x^3-x^2+x+39=0

The zeros of x^3-x^2+x+39=0 are x=-3,x=2+3i,x=2-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - x^{2} + x + 39 = 0

x = - 3, x = 2 + 3 i, x = 2 - 3 i

Solution steps

x^{3} - x^{2} + x + 39 = 0

Factor

x^{3} - x^{2} + x + 39 : (x + 3) (x^{2} - 4 x + 13)

(x + 3) (x^{2} - 4 x + 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x^{2} - 4 x + 13 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x^{2} - 4 x + 13 = 0 : x = 2 + 3 i, x = 2 - 3 i

The solutions are

x = - 3, x = 2 + 3 i, x = 2 - 3 i

t^{3} - 8 = 0

x^{8} = 46

x^{8} = 48

u^{3} - 1 = 1

z, z^{4} - 36 = 0

What are the solutions to the equation x^3-x^2+x+39=0 ?
The solutions to the equation x^3-x^2+x+39=0 are x=-3,x=2+3i,x=2-3i
Find the zeros of x^3-x^2+x+39=0
The zeros of x^3-x^2+x+39=0 are x=-3,x=2+3i,x=2-3i