What are the solutions to the equation v^3=1 ?

The solutions to the equation v^3=1 are v=1,v=-1/2+(sqrt(3))/2 i,v=-1/2-(sqrt(3))/2 i

Find the zeros of v^3=1

The zeros of v^3=1 are v=1,v=-1/2+(sqrt(3))/2 i,v=-1/2-(sqrt(3))/2 i

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v^{3} = 1

v = 1, v = - \frac{1}{2} + \frac{3}{2} i, v = - \frac{1}{2} - \frac{3}{2} i

Solution steps

v^{3} = 1

For

x^{3} = f (a)

the solutions are

v = 1, v = \frac{- 1 + 3 i}{2}, v = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

v = 1, v = - \frac{1}{2} + \frac{3}{2} i, v = - \frac{1}{2} - \frac{3}{2} i

v^{3} = 2

(2)^{2} = (x) (x + 1)^{2}

5 k^{3} = - 10 k^{2} + 5 k + 10

x^{4} + x^{2} = 20

s^{4} + 9 s^{2} + 14 = 0

What are the solutions to the equation v^3=1 ?
The solutions to the equation v^3=1 are v=1,v=-1/2+(sqrt(3))/2 i,v=-1/2-(sqrt(3))/2 i
Find the zeros of v^3=1
The zeros of v^3=1 are v=1,v=-1/2+(sqrt(3))/2 i,v=-1/2-(sqrt(3))/2 i