What are the solutions to the equation 2x^4=128x ?

The solutions to the equation 2x^4=128x are x=0,x=4,x=-2+2sqrt(3)i,x=-2-2sqrt(3)i

Find the zeros of 2x^4=128x

The zeros of 2x^4=128x are x=0,x=4,x=-2+2sqrt(3)i,x=-2-2sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{4} = 128 x

x = 0, x = 4, x = - 2 + 23 i, x = - 2 - 23 i

Solution steps

2 x^{4} = 128 x

Move

128 x

to the left side

2 x^{4} - 128 x = 0

Factor

2 x^{4} - 128 x : 2 x (x - 4) (x^{2} + 4 x + 16)

2 x (x - 4) (x^{2} + 4 x + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0 or x^{2} + 4 x + 16 = 0

Solve

x - 4 = 0 : x = 4

Solve

x^{2} + 4 x + 16 = 0 : x = - 2 + 23 i, x = - 2 - 23 i

The solutions are

x = 0, x = 4, x = - 2 + 23 i, x = - 2 - 23 i

x, 2 x y - x^{3} = 0

- 2 x^{3} + 3 = 0

3 x^{4} + 4 x^{3} + 6 x^{2} - 4 = 0

x^{3} - 2 x = 88

- 32 x^{5} + 160 x^{3} - 120 x = 0

What are the solutions to the equation 2x^4=128x ?
The solutions to the equation 2x^4=128x are x=0,x=4,x=-2+2sqrt(3)i,x=-2-2sqrt(3)i
Find the zeros of 2x^4=128x
The zeros of 2x^4=128x are x=0,x=4,x=-2+2sqrt(3)i,x=-2-2sqrt(3)i