What are the solutions to the equation 50(1+r)^{12}=10 ?

The solutions to the equation 50(1+r)^{12}=10 are r=\sqrt[12]{1/5}-1,r=-\sqrt[12]{1/5}-1

Find the zeros of 50(1+r)^{12}=10

The zeros of 50(1+r)^{12}=10 are r=\sqrt[12]{1/5}-1,r=-\sqrt[12]{1/5}-1

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50 (1 + r)^{12} = 10

Solution steps

50 (1 + r)^{12} = 10

Divide both sides by

50

(1 + r)^{12} = \frac{1}{5}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x, x^{3} - x^{2} - 10 x - 8 = 0

- x^{3} + 8 x^{2} + 21 x + 18 = 0

6 x^{4} - 17 x^{2} + 5 = 0

p^{3} - 3 p - 88 = 0

x, x^{20} + y^{5} = 3000

What are the solutions to the equation 50(1+r)^{12}=10 ?
The solutions to the equation 50(1+r)^{12}=10 are r=\sqrt[12]{1/5}-1,r=-\sqrt[12]{1/5}-1
Find the zeros of 50(1+r)^{12}=10
The zeros of 50(1+r)^{12}=10 are r=\sqrt[12]{1/5}-1,r=-\sqrt[12]{1/5}-1