What are the solutions to the equation x^3-5x^2=-4x ?

The solutions to the equation x^3-5x^2=-4x are x=0,x=1,x=4

Find the zeros of x^3-5x^2=-4x

The zeros of x^3-5x^2=-4x are x=0,x=1,x=4

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x^{3} - 5 x^{2} = - 4 x

x = 0, x = 1, x = 4

Solution steps

x^{3} - 5 x^{2} = - 4 x

Move

4 x

to the left side

x^{3} - 5 x^{2} + 4 x = 0

Factor

x^{3} - 5 x^{2} + 4 x : x (x - 1) (x - 4)

x (x - 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = 1, x = 4

3 x^{6} - 14 x^{3} = 80

6 x^{2} x = 2

x^{8} = xx + 5

270 x - 3 x^{2} - 3 x^{3} = 0

x^{3} - 100 x^{2} + 3200 x - 120 = 0

What are the solutions to the equation x^3-5x^2=-4x ?
The solutions to the equation x^3-5x^2=-4x are x=0,x=1,x=4
Find the zeros of x^3-5x^2=-4x
The zeros of x^3-5x^2=-4x are x=0,x=1,x=4