What are the solutions to the equation (2-x^2)^2-1=0 ?

The solutions to the equation (2-x^2)^2-1=0 are x=1,x=-1,x=sqrt(3),x=-sqrt(3)

Find the zeros of (2-x^2)^2-1=0

The zeros of (2-x^2)^2-1=0 are x=1,x=-1,x=sqrt(3),x=-sqrt(3)

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(2 - x^{2})^{2} - 1 = 0

x = 1, x = - 1, x = 3, x = - 3

Decimal Notation

x = 1, x = - 1, x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

(2 - x^{2})^{2} - 1 = 0

Move

1

to the right side

(2 - x^{2})^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 - x^{2} = 1 : x = 1, x = - 1

Solve

2 - x^{2} = - 1 : x = 3, x = - 3

The solutions are

x = 1, x = - 1, x = 3, x = - 3

m^{4} - 13 m^{2} + 36 = 0

z^{4} + 3 z^{2} + 2 = 0

x^{4} - 5 x^{2} - 6 = 0

x^{3} - x^{2} - 8 x - 12 = 0

x^{2 + 1} - 3 x + 1 = 0

What are the solutions to the equation (2-x^2)^2-1=0 ?
The solutions to the equation (2-x^2)^2-1=0 are x=1,x=-1,x=sqrt(3),x=-sqrt(3)
Find the zeros of (2-x^2)^2-1=0
The zeros of (2-x^2)^2-1=0 are x=1,x=-1,x=sqrt(3),x=-sqrt(3)