What are the solutions to the equation 4c^3+4c^2-224c=0 ?

The solutions to the equation 4c^3+4c^2-224c=0 are c=0,c=7,c=-8

Find the zeros of 4c^3+4c^2-224c=0

The zeros of 4c^3+4c^2-224c=0 are c=0,c=7,c=-8

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4 c^{3} + 4 c^{2} - 224 c = 0

c = 0, c = 7, c = - 8

Solution steps

4 c^{3} + 4 c^{2} - 224 c = 0

Factor

4 c^{3} + 4 c^{2} - 224 c : 4 c (c - 7) (c + 8)

4 c (c - 7) (c + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c = 0 or c - 7 = 0 or c + 8 = 0

Solve

c - 7 = 0 : c = 7

Solve

c + 8 = 0 : c = - 8

The solutions are

c = 0, c = 7, c = - 8

λ^{3} + λ = 0

- λ^{3} + 11 λ^{2} - 39 λ + 45 = 0

8 x^{3} - 10 x^{2} - 7 x - 1 = 0

- (x - 3) (x + 5) x^{2} + x - 8 = x - 3 x

x^{4} = 10000

What are the solutions to the equation 4c^3+4c^2-224c=0 ?
The solutions to the equation 4c^3+4c^2-224c=0 are c=0,c=7,c=-8
Find the zeros of 4c^3+4c^2-224c=0
The zeros of 4c^3+4c^2-224c=0 are c=0,c=7,c=-8