What are the solutions to the equation -32x^2+4x^3-x+8=0 ?

The solutions to the equation -32x^2+4x^3-x+8=0 are x=8,x=-1/2 ,x= 1/2

Find the zeros of -32x^2+4x^3-x+8=0

The zeros of -32x^2+4x^3-x+8=0 are x=8,x=-1/2 ,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 32 x^{2} + 4 x^{3} - x + 8 = 0

x = 8, x = - \frac{1}{2}, x = \frac{1}{2}

Solution steps

- 32 x^{2} + 4 x^{3} - x + 8 = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

4 x^{3} - 32 x^{2} - x + 8 = 0

Factor

4 x^{3} - 32 x^{2} - x + 8 : (x - 8) (2 x + 1) (2 x - 1)

(x - 8) (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 8 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

x - 8 = 0 : x = 8

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 8, x = - \frac{1}{2}, x = \frac{1}{2}

z, z^{4} - 9 = 0

- (x - 1)^{3} = 8

- (x - 1)^{3} = 0

(p^{8})^{2} = p^{10}

50 = 4 x^{3} - 44 x^{2} + 120 x

What are the solutions to the equation -32x^2+4x^3-x+8=0 ?
The solutions to the equation -32x^2+4x^3-x+8=0 are x=8,x=-1/2 ,x= 1/2
Find the zeros of -32x^2+4x^3-x+8=0
The zeros of -32x^2+4x^3-x+8=0 are x=8,x=-1/2 ,x= 1/2