What are the solutions to the equation v^3+1=0 ?

The solutions to the equation v^3+1=0 are v=-1,v= 1/2-(sqrt(3))/2 i,v= 1/2+(sqrt(3))/2 i

Find the zeros of v^3+1=0

The zeros of v^3+1=0 are v=-1,v= 1/2-(sqrt(3))/2 i,v= 1/2+(sqrt(3))/2 i

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v^{3} + 1 = 0

v = - 1, v = \frac{1}{2} - \frac{3}{2} i, v = \frac{1}{2} + \frac{3}{2} i

Solution steps

v^{3} + 1 = 0

Move

1

to the right side

v^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

v = - 1, v = \frac{1}{2} - \frac{3}{2} i, v = \frac{1}{2} + \frac{3}{2} i

- 2 x^{3} - 3 x^{2} - 15 x + 11 = 0

x, 2 x^{3} - 2 y^{3} = - 3

x^{4} + 6 x^{3} + 11 x^{2} + 6 x = 212520

x (x - 2) (3 x - 1) = 0

3 x^{3} - 2 x^{2} - 5 x = 0

What are the solutions to the equation v^3+1=0 ?
The solutions to the equation v^3+1=0 are v=-1,v= 1/2-(sqrt(3))/2 i,v= 1/2+(sqrt(3))/2 i
Find the zeros of v^3+1=0
The zeros of v^3+1=0 are v=-1,v= 1/2-(sqrt(3))/2 i,v= 1/2+(sqrt(3))/2 i