What are the solutions to the equation x^3-18x-8=0 ?

The solutions to the equation x^3-18x-8=0 are x=-4,x=2+sqrt(6),x=2-sqrt(6)

Find the zeros of x^3-18x-8=0

The zeros of x^3-18x-8=0 are x=-4,x=2+sqrt(6),x=2-sqrt(6)

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x^{3} - 18 x - 8 = 0

x = - 4, x = 2 + 6, x = 2 - 6

Decimal Notation

x = - 4, x = 4.44948 \dots, x = - 0.44948 \dots

Solution steps

x^{3} - 18 x - 8 = 0

Factor

x^{3} - 18 x - 8 : (x + 4) (x^{2} - 4 x - 2)

(x + 4) (x^{2} - 4 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x^{2} - 4 x - 2 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x^{2} - 4 x - 2 = 0 : x = 2 + 6, x = 2 - 6

The solutions are

x = - 4, x = 2 + 6, x = 2 - 6

e^{0.678} = x^{3}

384 = 3 (r^{8 - 1})

x^{3} + 0 x^{2} - 4 x + 2 = 0

3 c^{3} + 15 c^{2} - 18 c = 0

- 4 = x^{4} - 5 x^{2}

What are the solutions to the equation x^3-18x-8=0 ?
The solutions to the equation x^3-18x-8=0 are x=-4,x=2+sqrt(6),x=2-sqrt(6)
Find the zeros of x^3-18x-8=0
The zeros of x^3-18x-8=0 are x=-4,x=2+sqrt(6),x=2-sqrt(6)