What are the solutions to the equation 2^2x3^2=(2x^3)^2 ?

The solutions to the equation 2^2x3^2=(2x^3)^2 are x=0,x=\sqrt[5]{9}

Find the zeros of 2^2x3^2=(2x^3)^2

The zeros of 2^2x3^2=(2x^3)^2 are x=0,x=\sqrt[5]{9}

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2^{2} x 3^{2} = (2 x^{3})^{2}

Solution steps

2^{2} x \cdot 3^{2} = (2 x^{3})^{2}

Switch sides

(2 x^{3})^{2} = 2^{2} x \cdot 3^{2}

Move

2^{2} x 3^{2}

to the left side

2^{2} x^{6} - 2^{2} x \cdot 3^{2} = 0

Factor

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

No Solution for

x \in R

The solutions are

0 = 4 x^{3} - 45 x^{2} - 4 x + 40

(- 8 - x) (- x + 2) (- x + 1) = 0

x^{3} - 2 x^{2} + 4 = 0

x^{6} + 2 x^{2} + 1 = 0

2 x^{3} - 28 x^{2} + 80 x = 0

What are the solutions to the equation 2^2x3^2=(2x^3)^2 ?
The solutions to the equation 2^2x3^2=(2x^3)^2 are x=0,x=\sqrt[5]{9}
Find the zeros of 2^2x3^2=(2x^3)^2
The zeros of 2^2x3^2=(2x^3)^2 are x=0,x=\sqrt[5]{9}