What are the solutions to the equation -(a+1)^2(a-8)=0 ?

The solutions to the equation -(a+1)^2(a-8)=0 are a=-1,a=8

Find the zeros of -(a+1)^2(a-8)=0

The zeros of -(a+1)^2(a-8)=0 are a=-1,a=8

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- (a + 1)^{2} (a - 8) = 0

a = - 1, a = 8

Solution steps

- (a + 1)^{2} (a - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a + 1 = 0 or a - 8 = 0

Solve

a + 1 = 0 : a = - 1

Solve

a - 8 = 0 : a = 8

The solutions are

a = - 1, a = 8

x^{2} + 6 x + 9 = 4 x^{4}

m^{7} - 3 = 0

1400 = 700 (1 + \frac{x}{100})^{5}

\frac{x x ^{8}}{5} = \frac{- 2}{25}

x^{5} + 3 x^{3} - 10 x = 0

What are the solutions to the equation -(a+1)^2(a-8)=0 ?
The solutions to the equation -(a+1)^2(a-8)=0 are a=-1,a=8
Find the zeros of -(a+1)^2(a-8)=0
The zeros of -(a+1)^2(a-8)=0 are a=-1,a=8