What are the solutions to the equation x^3+6x^2-28x-96=0 ?

The solutions to the equation x^3+6x^2-28x-96=0 are x=-8,x=1+sqrt(13),x=1-sqrt(13)

Find the zeros of x^3+6x^2-28x-96=0

The zeros of x^3+6x^2-28x-96=0 are x=-8,x=1+sqrt(13),x=1-sqrt(13)

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x^{3} + 6 x^{2} - 28 x - 96 = 0

x = - 8, x = 1 + 13, x = 1 - 13

Solution steps

x^{3} + 6 x^{2} - 28 x - 96 = 0

Factor

x^{3} + 6 x^{2} - 28 x - 96 : (x + 8) (x^{2} - 2 x - 12)

(x + 8) (x^{2} - 2 x - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or x^{2} - 2 x - 12 = 0

Solve

x + 8 = 0 : x = - 8

Solve

x^{2} - 2 x - 12 = 0 : x = 1 + 13, x = 1 - 13

The solutions are

x = - 8, x = 1 + 13, x = 1 - 13

x^{8} - x^{4} - 30 = 0

4 x^{3} - x^{2} + 100 x - 25 = 0

z^{4} + 4 z^{3} + 2 z^{2} - 12 z - 15 = 0

3 a^{3} - 147 a = - 2 a^{2} + 98

695 = 5 x^{3}

What are the solutions to the equation x^3+6x^2-28x-96=0 ?
The solutions to the equation x^3+6x^2-28x-96=0 are x=-8,x=1+sqrt(13),x=1-sqrt(13)
Find the zeros of x^3+6x^2-28x-96=0
The zeros of x^3+6x^2-28x-96=0 are x=-8,x=1+sqrt(13),x=1-sqrt(13)