What are the solutions to the equation 3w-w^3=2 ?

The solutions to the equation 3w-w^3=2 are w=1,w=-2

Find the zeros of 3w-w^3=2

The zeros of 3w-w^3=2 are w=1,w=-2

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3 w - w^{3} = 2

w = 1, w = - 2

Solution steps

3 w - w^{3} = 2

Move

2

to the left side

3 w - w^{3} - 2 = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- w^{3} + 3 w - 2 = 0

Factor

- w^{3} + 3 w - 2 : - (w - 1)^{2} (w + 2)

- (w - 1)^{2} (w + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

w - 1 = 0 or w + 2 = 0

Solve

w - 1 = 0 : w = 1

Solve

w + 2 = 0 : w = - 2

The solutions are

w = 1, w = - 2

x^{5} = 1 0^{35}

y^{3} y - 5 = 19

x^{4} + 8 x - 8 = 0

x^{4} - 4 x^{3} - 7 x^{2} + 22 x + 24 = 0

z^{3} = - 2

What are the solutions to the equation 3w-w^3=2 ?
The solutions to the equation 3w-w^3=2 are w=1,w=-2
Find the zeros of 3w-w^3=2
The zeros of 3w-w^3=2 are w=1,w=-2