What are the solutions to the equation x^3-8x^2+x+42=0 ?

The solutions to the equation x^3-8x^2+x+42=0 are x=-2,x=3,x=7

Find the zeros of x^3-8x^2+x+42=0

The zeros of x^3-8x^2+x+42=0 are x=-2,x=3,x=7

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x^{3} - 8 x^{2} + x + 42 = 0

x = - 2, x = 3, x = 7

Solution steps

x^{3} - 8 x^{2} + x + 42 = 0

Factor

x^{3} - 8 x^{2} + x + 42 : (x + 2) (x - 3) (x - 7)

(x + 2) (x - 3) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 3 = 0 or x - 7 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

Solve

x - 7 = 0 : x = 7

The solutions are

x = - 2, x = 3, x = 7

(x - 4)^{4} = 81

- \frac{1}{4} x^{5} = 8

(2 x - 4)^{2} + 6 x - 3 = 4 x^{3} - (3 x - 1)

x^{3} - 12 x^{2} - 60 x + 400 = 0

6 x^{3} - 11 x^{2} + 28 x + 5 = 0

What are the solutions to the equation x^3-8x^2+x+42=0 ?
The solutions to the equation x^3-8x^2+x+42=0 are x=-2,x=3,x=7
Find the zeros of x^3-8x^2+x+42=0
The zeros of x^3-8x^2+x+42=0 are x=-2,x=3,x=7