What are the solutions to the equation 128x^3-16x=0 ?

The solutions to the equation 128x^3-16x=0 are x=0,x=-1/(2sqrt(2)),x= 1/(2sqrt(2))

Find the zeros of 128x^3-16x=0

The zeros of 128x^3-16x=0 are x=0,x=-1/(2sqrt(2)),x= 1/(2sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

128 x^{3} - 16 x = 0

x = 0, x = - \frac{1}{2 2}, x = \frac{1}{2 2}

Solution steps

128 x^{3} - 16 x = 0

Factor

128 x^{3} - 16 x : 16 x (22 x + 1) (22 x - 1)

16 x (22 x + 1) (22 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 22 x + 1 = 0 or 22 x - 1 = 0

Solve

22 x + 1 = 0 : x = - \frac{1}{2 2}

Solve

22 x - 1 = 0 : x = \frac{1}{2 2}

The solutions are

x = 0, x = - \frac{1}{2 2}, x = \frac{1}{2 2}

x^{4} + a^{2} = 0

(4 - x^{2})^{2} = 23 - 2 x^{2}

(v - 1) (v^{2} + v - 4) = 0

4 x^{4} + 2 x^{2} - 56 = 0

0 = 2 x^{3} - 3 x + 1

What are the solutions to the equation 128x^3-16x=0 ?
The solutions to the equation 128x^3-16x=0 are x=0,x=-1/(2sqrt(2)),x= 1/(2sqrt(2))
Find the zeros of 128x^3-16x=0
The zeros of 128x^3-16x=0 are x=0,x=-1/(2sqrt(2)),x= 1/(2sqrt(2))