What are the solutions to the equation 6x^3+x^2-24x-4=0 ?

The solutions to the equation 6x^3+x^2-24x-4=0 are x=-1/6 ,x=-2,x=2

Find the zeros of 6x^3+x^2-24x-4=0

The zeros of 6x^3+x^2-24x-4=0 are x=-1/6 ,x=-2,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{3} + x^{2} - 24 x - 4 = 0

x = - \frac{1}{6}, x = - 2, x = 2

Solution steps

6 x^{3} + x^{2} - 24 x - 4 = 0

Factor

6 x^{3} + x^{2} - 24 x - 4 : (6 x + 1) (x + 2) (x - 2)

(6 x + 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 x + 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

6 x + 1 = 0 : x = - \frac{1}{6}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{1}{6}, x = - 2, x = 2

x, x^{3} + y^{3} = 27

x^{3} + 6 x^{2} - 81 = 0

x, x^{3} + y^{3} = 18

x, x^{3} = \frac{y}{2}

x (1 - \frac{x ^{3}}{2000}) = 0

What are the solutions to the equation 6x^3+x^2-24x-4=0 ?
The solutions to the equation 6x^3+x^2-24x-4=0 are x=-1/6 ,x=-2,x=2
Find the zeros of 6x^3+x^2-24x-4=0
The zeros of 6x^3+x^2-24x-4=0 are x=-1/6 ,x=-2,x=2