What are the solutions to the equation 2x^3-12x^2+16x=0 ?

The solutions to the equation 2x^3-12x^2+16x=0 are x=0,x=2,x=4

Find the zeros of 2x^3-12x^2+16x=0

The zeros of 2x^3-12x^2+16x=0 are x=0,x=2,x=4

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2 x^{3} - 12 x^{2} + 16 x = 0

x = 0, x = 2, x = 4

Solution steps

2 x^{3} - 12 x^{2} + 16 x = 0

Factor

2 x^{3} - 12 x^{2} + 16 x : 2 x (x - 2) (x - 4)

2 x (x - 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = 2, x = 4

x, x^{3} + y^{3} = 36

5 x^{3} - 24 x^{2} + 12 x + 8 = 0

x^{3} + 2 x - 9 x - 18 = 0

x^{3} + x^{2} - 5 = 0

x^{2} (x + 8)^{2} = 140

What are the solutions to the equation 2x^3-12x^2+16x=0 ?
The solutions to the equation 2x^3-12x^2+16x=0 are x=0,x=2,x=4
Find the zeros of 2x^3-12x^2+16x=0
The zeros of 2x^3-12x^2+16x=0 are x=0,x=2,x=4