What are the solutions to the equation x^3+9x^2+17x+6=0 ?

The solutions to the equation x^3+9x^2+17x+6=0 are x=-2,x=(-7+sqrt(37))/2 ,x=(-7-sqrt(37))/2

Find the zeros of x^3+9x^2+17x+6=0

The zeros of x^3+9x^2+17x+6=0 are x=-2,x=(-7+sqrt(37))/2 ,x=(-7-sqrt(37))/2

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x^{3} + 9 x^{2} + 17 x + 6 = 0

x = - 2, x = \frac{- 7 + 37}{2}, x = \frac{- 7 - 37}{2}

Solution steps

x^{3} + 9 x^{2} + 17 x + 6 = 0

Factor

x^{3} + 9 x^{2} + 17 x + 6 : (x + 2) (x^{2} + 7 x + 3)

(x + 2) (x^{2} + 7 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 7 x + 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 7 x + 3 = 0 : x = \frac{- 7 + 37}{2}, x = \frac{- 7 - 37}{2}

The solutions are

x = - 2, x = \frac{- 7 + 37}{2}, x = \frac{- 7 - 37}{2}

x^{6} + 16 = 0

b^{3} = 44

x^{3} + 4 x = 5

x^{3} + 4 x = 8

3 x^{4} - 74 x^{2} - 25 = 0

What are the solutions to the equation x^3+9x^2+17x+6=0 ?
The solutions to the equation x^3+9x^2+17x+6=0 are x=-2,x=(-7+sqrt(37))/2 ,x=(-7-sqrt(37))/2
Find the zeros of x^3+9x^2+17x+6=0
The zeros of x^3+9x^2+17x+6=0 are x=-2,x=(-7+sqrt(37))/2 ,x=(-7-sqrt(37))/2