What are the solutions to the equation 3x^4-3x+23=4 ?

The solutions to the equation 3x^4-3x+23=4 are No Solution for x\in\mathbb{R}

Find the zeros of 3x^4-3x+23=4

The zeros of 3x^4-3x+23=4 are No Solution for x\in\mathbb{R}

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3 x^{4} - 3 x + 23 = 4

No Solution for x \in R

Solution steps

3 x^{4} - 3 x + 23 = 4

Move

4

to the left side

3 x^{4} - 3 x + 19 = 0

Find one solution for

3 x^{4} - 3 x + 19 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

x^{3} (x^{2} - 10) = - 9 x

x^{3} - 2 x^{2} + x = 2 x - 2

2^{3} = x^{12}

6 x^{3} + 7 x^{2} - 1 = 0

x^{3} + x^{2} + 2 x + 5 = 0

What are the solutions to the equation 3x^4-3x+23=4 ?
The solutions to the equation 3x^4-3x+23=4 are No Solution for x\in\mathbb{R}
Find the zeros of 3x^4-3x+23=4
The zeros of 3x^4-3x+23=4 are No Solution for x\in\mathbb{R}