What are the solutions to the equation (x+4)*(-4x^2+4x-1)=0 ?

The solutions to the equation (x+4)*(-4x^2+4x-1)=0 are x=-4,x= 1/2

Find the zeros of (x+4)*(-4x^2+4x-1)=0

The zeros of (x+4)*(-4x^2+4x-1)=0 are x=-4,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 4) \cdot (- 4 x^{2} + 4 x - 1) = 0

x = - 4, x = \frac{1}{2}

Decimal Notation

x = - 4, x = 0.5

Solution steps

(x + 4) (- 4 x^{2} + 4 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or - 4 x^{2} + 4 x - 1 = 0

Solve

x + 4 = 0 : x = - 4

Solve

- 4 x^{2} + 4 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = - 4, x = \frac{1}{2}

n^{4} (n + 5) - 2 (5 + 7 n) = - 70

z^{4} = 6 z^{2} + 7

7 z^{3} + 30 z^{2} = 25 z

s^{3} + 9.5 s^{2} - 5 s = 0

1 - k^{4} = 0.4583

What are the solutions to the equation (x+4)*(-4x^2+4x-1)=0 ?
The solutions to the equation (x+4)*(-4x^2+4x-1)=0 are x=-4,x= 1/2
Find the zeros of (x+4)*(-4x^2+4x-1)=0
The zeros of (x+4)*(-4x^2+4x-1)=0 are x=-4,x= 1/2