What are the solutions to the equation 9x(2x+1)^3=4x(2x+1) ?

The solutions to the equation 9x(2x+1)^3=4x(2x+1) are x=0,x=-1/2 ,x=-1/6 ,x=-5/6

Find the zeros of 9x(2x+1)^3=4x(2x+1)

The zeros of 9x(2x+1)^3=4x(2x+1) are x=0,x=-1/2 ,x=-1/6 ,x=-5/6

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9 x (2 x + 1)^{3} = 4 x (2 x + 1)

x = 0, x = - \frac{1}{2}, x = - \frac{1}{6}, x = - \frac{5}{6}

Decimal Notation

x = 0, x = - 0.5, x = - 0.16666 \dots, x = - 0.83333 \dots

Solution steps

9 x (2 x + 1)^{3} = 4 x (2 x + 1)

Move

4 x (2 x + 1)

to the left side

9 x (2 x + 1)^{3} - 4 x (2 x + 1) = 0

Factor

9 x (2 x + 1)^{3} - 4 x (2 x + 1) : x (2 x + 1) (6 x + 1) (6 x + 5)

x (2 x + 1) (6 x + 1) (6 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0 or 6 x + 1 = 0 or 6 x + 5 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

6 x + 1 = 0 : x = - \frac{1}{6}

Solve

6 x + 5 = 0 : x = - \frac{5}{6}

The solutions are

x = 0, x = - \frac{1}{2}, x = - \frac{1}{6}, x = - \frac{5}{6}

(4 x - 1) (5 x^{3} - 8.64) = 0

s^{5} + s^{2} + s = 0

x, 2 x^{4} + 3 = y^{2}

4 x^{3} - 52 x^{2} + 160 x - 100 = 0

x, f = (x + 1)^{3}

What are the solutions to the equation 9x(2x+1)^3=4x(2x+1) ?
The solutions to the equation 9x(2x+1)^3=4x(2x+1) are x=0,x=-1/2 ,x=-1/6 ,x=-5/6
Find the zeros of 9x(2x+1)^3=4x(2x+1)
The zeros of 9x(2x+1)^3=4x(2x+1) are x=0,x=-1/2 ,x=-1/6 ,x=-5/6