What are the solutions to the equation x^3+2=1 ?

The solutions to the equation x^3+2=1 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i

Find the zeros of x^3+2=1

The zeros of x^3+2=1 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i

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x^{3} + 2 = 1

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

Solution steps

x^{3} + 2 = 1

Move

2

to the right side

x^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

- x^{3} + 2 \cdot x^{2} + x - 2 = 0

300 x^{4} + 480 x^{3} + 180 x^{2} = 0

2 x^{2} - 5 x^{3} + 1 = 0

x^{3} + 2 = 9

3 x^{3} - x^{2} + 6 x - 2 = 0

What are the solutions to the equation x^3+2=1 ?
The solutions to the equation x^3+2=1 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i
Find the zeros of x^3+2=1
The zeros of x^3+2=1 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i