What are the solutions to the equation x^3-8x=2x^2 ?

The solutions to the equation x^3-8x=2x^2 are x=0,x=-2,x=4

Find the zeros of x^3-8x=2x^2

The zeros of x^3-8x=2x^2 are x=0,x=-2,x=4

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x^{3} - 8 x = 2 x^{2}

x = 0, x = - 2, x = 4

Solution steps

x^{3} - 8 x = 2 x^{2}

Move

2 x^{2}

to the left side

x^{3} - 8 x - 2 x^{2} = 0

Factor

x^{3} - 8 x - 2 x^{2} : x (x + 2) (x - 4)

x (x + 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = - 2, x = 4

x, y - 1 = x^{3}

x^{3} + 2 = 345

6 x^{3} - x^{2} - 35 x = 0

x^{4} + 7 x^{3} - 2 x^{2} + 7 x + 1 = 0

x^{4} = 3 x

What are the solutions to the equation x^3-8x=2x^2 ?
The solutions to the equation x^3-8x=2x^2 are x=0,x=-2,x=4
Find the zeros of x^3-8x=2x^2
The zeros of x^3-8x=2x^2 are x=0,x=-2,x=4