What are the solutions to the equation 2x^4-16x=0 ?

The solutions to the equation 2x^4-16x=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of 2x^4-16x=0

The zeros of 2x^4-16x=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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2 x^{4} - 16 x = 0

x = 0, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

2 x^{4} - 16 x = 0

Factor

2 x^{4} - 16 x : 2 x (x^{3} - 8)

2 x (x^{3} - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{3} - 8 = 0

Solve

x^{3} - 8 = 0 : x = 2, x = - 1 + 3 i, x = - 1 - 3 i

The solutions are

x = 0, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

36 - 12 x - 4 x^{3} = 0

(x - 3)^{3} + 18 = 530

x + 4 = ((x^{2} - 4 x) - 2)^{2}

x^{3} - x^{2} - 8 x + 10 = 0

x^{3} + 4 x - 2 = 0

What are the solutions to the equation 2x^4-16x=0 ?
The solutions to the equation 2x^4-16x=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of 2x^4-16x=0
The zeros of 2x^4-16x=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i