What are the solutions to the equation x^4-2x^3+5x^2-6=0 ?

The solutions to the equation x^4-2x^3+5x^2-6=0 are x\approx 1.21756…,x\approx-0.89012…

Find the zeros of x^4-2x^3+5x^2-6=0

The zeros of x^4-2x^3+5x^2-6=0 are x\approx 1.21756…,x\approx-0.89012…

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x^{4} - 2 x^{3} + 5 x^{2} - 6 = 0

x \approx 1.21756 \dots, x \approx - 0.89012 \dots

Solution steps

x^{4} - 2 x^{3} + 5 x^{2} - 6 = 0

Find one solution for

x^{4} - 2 x^{3} + 5 x^{2} - 6 = 0

using Newton-Raphson:

x \approx 1.21756 \dots

Apply long division:

\frac{x ^{4} - 2 x ^{3} + 5 x ^{2} - 6}{x - 1.21756 \dots} = x^{3} - 0.78243 \dots x^{2} + 4.04733 \dots x + 4.92787 \dots

x^{3} - 0.78243 \dots x^{2} + 4.04733 \dots x + 4.92787 \dots \approx 0

Find one solution for

x^{3} - 0.78243 \dots x^{2} + 4.04733 \dots x + 4.92787 \dots = 0

using Newton-Raphson:

x \approx - 0.89012 \dots

Apply long division:

\frac{x ^{3} - 0.78243 \dots x ^{2} + 4.04733 \dots x + 4.92787 \dots}{x + 0.89012 \dots} = x^{2} - 1.67256 \dots x + 5.53613 \dots

x^{2} - 1.67256 \dots x + 5.53613 \dots \approx 0

Find one solution for

x^{2} - 1.67256 \dots x + 5.53613 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solutions are

x \approx 1.21756 \dots, x \approx - 0.89012 \dots

a, 2 f = 5 a^{5}

(x + 1) (x + 2) (x + 3) (x + 6) = - x^{2}

2 = (1 + x)^{4}

y, A = \frac{k y ^{4}}{S}

2 x^{4} + x^{4} - 6 = 0

What are the solutions to the equation x^4-2x^3+5x^2-6=0 ?
The solutions to the equation x^4-2x^3+5x^2-6=0 are x\approx 1.21756…,x\approx-0.89012…
Find the zeros of x^4-2x^3+5x^2-6=0
The zeros of x^4-2x^3+5x^2-6=0 are x\approx 1.21756…,x\approx-0.89012…