What are the solutions to the equation x^2(4x-3)(5x-1)=0 ?

The solutions to the equation x^2(4x-3)(5x-1)=0 are x=0,x= 3/4 ,x= 1/5

Find the zeros of x^2(4x-3)(5x-1)=0

The zeros of x^2(4x-3)(5x-1)=0 are x=0,x= 3/4 ,x= 1/5

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x^{2} (4 x - 3) (5 x - 1) = 0

x = 0, x = \frac{3}{4}, x = \frac{1}{5}

Decimal Notation

x = 0, x = 0.75, x = 0.2

Solution steps

x^{2} (4 x - 3) (5 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x - 3 = 0 or 5 x - 1 = 0

Solve

4 x - 3 = 0 : x = \frac{3}{4}

Solve

5 x - 1 = 0 : x = \frac{1}{5}

The solutions are

x = 0, x = \frac{3}{4}, x = \frac{1}{5}

x^{8} = 1 0^{72}

x^{3} - 7 x^{2} + 13 x - 3 = 0

- x^{3} + 14 x^{2} - 42 x = 0

0 = x^{3} + x^{2} - x - 1

4 x^{3} + 2 x^{2} = 0

What are the solutions to the equation x^2(4x-3)(5x-1)=0 ?
The solutions to the equation x^2(4x-3)(5x-1)=0 are x=0,x= 3/4 ,x= 1/5
Find the zeros of x^2(4x-3)(5x-1)=0
The zeros of x^2(4x-3)(5x-1)=0 are x=0,x= 3/4 ,x= 1/5