What are the solutions to the equation 1+x+2x^2+3x^3+4x^4=0 ?

The solutions to the equation 1+x+2x^2+3x^3+4x^4=0 are No Solution for x\in\mathbb{R}

Find the zeros of 1+x+2x^2+3x^3+4x^4=0

The zeros of 1+x+2x^2+3x^3+4x^4=0 are No Solution for x\in\mathbb{R}

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1 + x + 2 x^{2} + 3 x^{3} + 4 x^{4} = 0

No Solution for x \in R

Solution steps

1 + x + 2 x^{2} + 3 x^{3} + 4 x^{4} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

4 x^{4} + 3 x^{3} + 2 x^{2} + x + 1 = 0

Find one solution for

4 x^{4} + 3 x^{3} + 2 x^{2} + x + 1 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

4 x^{2} (x + 8) = 0

6 x 1 9^{2} - 174 x^{19} + 1140 = 0

x^{4} + x - 6 = 0

y^{3} + y^{2} - 30 y = 0

3 (2 + 4 n) = 3 x^{2} + 3 x^{4} n

What are the solutions to the equation 1+x+2x^2+3x^3+4x^4=0 ?
The solutions to the equation 1+x+2x^2+3x^3+4x^4=0 are No Solution for x\in\mathbb{R}
Find the zeros of 1+x+2x^2+3x^3+4x^4=0
The zeros of 1+x+2x^2+3x^3+4x^4=0 are No Solution for x\in\mathbb{R}