What are the solutions to the equation (x^2-3x)^2=16 ?

The solutions to the equation (x^2-3x)^2=16 are x=4,x=-1,x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2

Find the zeros of (x^2-3x)^2=16

The zeros of (x^2-3x)^2=16 are x=4,x=-1,x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2

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(x^{2} - 3 x)^{2} = 16

x = 4, x = - 1, x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

Solution steps

(x^{2} - 3 x)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x^{2} - 3 x = 16 : x = 4, x = - 1

Solve

x^{2} - 3 x = - 16 : x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

The solutions are

x = 4, x = - 1, x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

2 x^{3} + x + 3 = 0

(x^{2} - 3 x + 2)^{7} = (x - 6 x + 5)^{7}

3 x^{3} - 15 x^{2} - 42 x = 0

2 x^{5} - x^{3} + 2 x^{2} = 1

m^{10} + 8 m = - 10 m - 8

What are the solutions to the equation (x^2-3x)^2=16 ?
The solutions to the equation (x^2-3x)^2=16 are x=4,x=-1,x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2
Find the zeros of (x^2-3x)^2=16
The zeros of (x^2-3x)^2=16 are x=4,x=-1,x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2