What are the solutions to the equation x*(2x-4)^2=0 ?

The solutions to the equation x*(2x-4)^2=0 are x=0,x=2

Find the zeros of x*(2x-4)^2=0

The zeros of x*(2x-4)^2=0 are x=0,x=2

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x \cdot (2 x - 4)^{2} = 0

x = 0, x = 2

Solution steps

x (2 x - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 4 = 0

Solve

2 x - 4 = 0 : x = 2

The solutions are

x = 0, x = 2

x, 3 x^{3} + x^{2} - 8 x + 4 = 0

\frac{5 x - 6}{3} = x^{5}

f = f^{5}

d^{3} = 729

3 x^{3} + 4 x^{2} - 5 x - 2 = 0

What are the solutions to the equation x*(2x-4)^2=0 ?
The solutions to the equation x*(2x-4)^2=0 are x=0,x=2
Find the zeros of x*(2x-4)^2=0
The zeros of x*(2x-4)^2=0 are x=0,x=2