What are the solutions to the equation 5x(x+2)+6=3 ?

The solutions to the equation 5x(x+2)+6=3 are x=(-5+sqrt(10))/5 ,x=-(5+sqrt(10))/5

Find the zeros of 5x(x+2)+6=3

The zeros of 5x(x+2)+6=3 are x=(-5+sqrt(10))/5 ,x=-(5+sqrt(10))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x (x + 2) + 6 = 3

x = \frac{- 5 + 10}{5}, x = - \frac{5 + 10}{5}

Decimal Notation

x = - 0.36754 \dots, x = - 1.63245 \dots

Solution steps

5 x (x + 2) + 6 = 3

Expand

5 x (x + 2) + 6 : 5 x^{2} + 10 x + 6

5 x^{2} + 10 x + 6 = 3

Move

3

to the left side

5 x^{2} + 10 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 \cdot 3 = 210

x_{1, 2} = \frac{- 10 \pm 2 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 10 + 2 10}{2 \cdot 5}, x_{2} = \frac{- 10 - 2 10}{2 \cdot 5}

x = \frac{- 10 + 2 10}{2 \cdot 5} : \frac{- 5 + 10}{5}

x = \frac{- 10 - 2 10}{2 \cdot 5} : - \frac{5 + 10}{5}

The solutions to the quadratic equation are:

x = \frac{- 5 + 10}{5}, x = - \frac{5 + 10}{5}

x^{2} + 5 x + \frac{10}{4}

+ 4 - 39 - 27 + 90

\frac{x}{- 4} - 5 = - 8

(- \frac{1}{2} + \frac{3}{2} i)^{3}

- 4 + x = 6

What are the solutions to the equation 5x(x+2)+6=3 ?
The solutions to the equation 5x(x+2)+6=3 are x=(-5+sqrt(10))/5 ,x=-(5+sqrt(10))/5
Find the zeros of 5x(x+2)+6=3
The zeros of 5x(x+2)+6=3 are x=(-5+sqrt(10))/5 ,x=-(5+sqrt(10))/5