What are the solutions to the equation 36y^2-27y=12y^3 ?

The solutions to the equation 36y^2-27y=12y^3 are y=0,y= 3/2

Find the zeros of 36y^2-27y=12y^3

The zeros of 36y^2-27y=12y^3 are y=0,y= 3/2

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36 y^{2} - 27 y = 12 y^{3}

y = 0, y = \frac{3}{2}

Decimal Notation

y = 0, y = 1.5

Solution steps

36 y^{2} - 27 y = 12 y^{3}

Switch sides

12 y^{3} = 36 y^{2} - 27 y

Move

27 y

to the left side

12 y^{3} + 27 y = 36 y^{2}

Move

36 y^{2}

to the left side

12 y^{3} + 27 y - 36 y^{2} = 0

Factor

12 y^{3} + 27 y - 36 y^{2} : 3 y (2 y - 3)^{2}

3 y (2 y - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 2 y - 3 = 0

Solve

2 y - 3 = 0 : y = \frac{3}{2}

The solutions are

y = 0, y = \frac{3}{2}

2 (- 2 + r^{7}) + 1 + r^{8} + 4 + r^{6} = 1

x^{3} + 3 x^{2} + 3 x + 2 = x + 2

2 x^{3} - 10 x^{2} - 3 x + 15 = 0

x^{3} + 3 x^{2} + x - 1 = 0

1398 y^{2} - y^{3} - 319 = 0

What are the solutions to the equation 36y^2-27y=12y^3 ?
The solutions to the equation 36y^2-27y=12y^3 are y=0,y= 3/2
Find the zeros of 36y^2-27y=12y^3
The zeros of 36y^2-27y=12y^3 are y=0,y= 3/2