What are the solutions to the equation x^3-2x^2-x+1=x^2-3x+1 ?

The solutions to the equation x^3-2x^2-x+1=x^2-3x+1 are x=0,x=1,x=2

Find the zeros of x^3-2x^2-x+1=x^2-3x+1

The zeros of x^3-2x^2-x+1=x^2-3x+1 are x=0,x=1,x=2

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x^{3} - 2 x^{2} - x + 1 = x^{2} - 3 x + 1

x = 0, x = 1, x = 2

Solution steps

x^{3} - 2 x^{2} - x + 1 = x^{2} - 3 x + 1

Move

1

to the right side

x^{3} - 2 x^{2} - x = x^{2} - 3 x

Move

3 x

to the left side

x^{3} - 2 x^{2} + 2 x = x^{2}

Move

x^{2}

to the left side

x^{3} - 3 x^{2} + 2 x = 0

Factor

x^{3} - 3 x^{2} + 2 x : x (x - 1) (x - 2)

x (x - 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 1, x = 2

y, 9 y^{4} - 7 y^{2} = 16

x^{6} + 4 x^{3} - 1 = 0

x, x^{4} + 3 x^{2} - 4 = 0

a^{4} - 1 = 0

3 x^{4} - 5 x^{2} - 2 = 0

What are the solutions to the equation x^3-2x^2-x+1=x^2-3x+1 ?
The solutions to the equation x^3-2x^2-x+1=x^2-3x+1 are x=0,x=1,x=2
Find the zeros of x^3-2x^2-x+1=x^2-3x+1
The zeros of x^3-2x^2-x+1=x^2-3x+1 are x=0,x=1,x=2