What are the solutions to the equation -(x+2)^3=0 ?

The solutions to the equation -(x+2)^3=0 are x=-2

Find the zeros of -(x+2)^3=0

The zeros of -(x+2)^3=0 are x=-2

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- (x + 2)^{3} = 0

x = - 2

Solution steps

- (x + 2)^{3} = 0

Divide both sides by

- 1

(x + 2)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x + 2 = 0 : x = - 2

The solution is

x = - 2

x^{4} + 15 x^{3} + 40 x^{2} - 39 x + 55 = 0

x, x^{5} + y^{5} = z^{5}

4 (x - 5)^{3} = 0

x^{4} - 4 x^{3} + 7 x^{2} - 16 x + 12 = 0

2 0^{2} = 0^{2} + (2 a^{40})

What are the solutions to the equation -(x+2)^3=0 ?
The solutions to the equation -(x+2)^3=0 are x=-2
Find the zeros of -(x+2)^3=0
The zeros of -(x+2)^3=0 are x=-2