What are the solutions to the equation 2x^3-3x^2+12=0 ?

The solutions to the equation 2x^3-3x^2+12=0 are x\approx-1.43080…

Find the zeros of 2x^3-3x^2+12=0

The zeros of 2x^3-3x^2+12=0 are x\approx-1.43080…

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2 x^{3} - 3 x^{2} + 12 = 0

x \approx - 1.43080 \dots

Solution steps

2 x^{3} - 3 x^{2} + 12 = 0

Find one solution for

2 x^{3} - 3 x^{2} + 12 = 0

using Newton-Raphson:

x \approx - 1.43080 \dots

Apply long division:

\frac{2 x ^{3} - 3 x ^{2} + 12}{x + 1.43080 \dots} = 2 x^{2} - 5.86161 \dots x + 8.38686 \dots

2 x^{2} - 5.86161 \dots x + 8.38686 \dots \approx 0

Find one solution for

2 x^{2} - 5.86161 \dots x + 8.38686 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 1.43080 \dots

535 = 5 x^{3}

4 π r^{4} + π r^{3} - 2000 r + 1000 = 0

s^{4} + 29 s^{2} + 60 s + 10 = 0

(2 x - 1)^{3} + 12 (x - 1) (x + 1) = 14 x - 13

x^{3} + 6 = - 12

What are the solutions to the equation 2x^3-3x^2+12=0 ?
The solutions to the equation 2x^3-3x^2+12=0 are x\approx-1.43080…
Find the zeros of 2x^3-3x^2+12=0
The zeros of 2x^3-3x^2+12=0 are x\approx-1.43080…