What are the solutions to the equation 4x^3-20x-9=0 ?

The solutions to the equation 4x^3-20x-9=0 are x\approx-0.47088…,x\approx-1.96312…,x\approx 2.43400…

Find the zeros of 4x^3-20x-9=0

The zeros of 4x^3-20x-9=0 are x\approx-0.47088…,x\approx-1.96312…,x\approx 2.43400…

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4 x^{3} - 20 x - 9 = 0

x \approx - 0.47088 \dots, x \approx - 1.96312 \dots, x \approx 2.43400 \dots

Solution steps

4 x^{3} - 20 x - 9 = 0

Find one solution for

4 x^{3} - 20 x - 9 = 0

using Newton-Raphson:

x \approx - 0.47088 \dots

Apply long division:

\frac{4 x ^{3} - 20 x - 9}{x + 0.47088 \dots} = 4 x^{2} - 1.88352 \dots x - 19.11308 \dots

4 x^{2} - 1.88352 \dots x - 19.11308 \dots \approx 0

Find one solution for

4 x^{2} - 1.88352 \dots x - 19.11308 \dots = 0

using Newton-Raphson:

x \approx - 1.96312 \dots

Apply long division:

\frac{4 x ^{2} - 1.88352 \dots x - 19.11308 \dots}{x + 1.96312 \dots} = 4 x - 9.73603 \dots

4 x - 9.73603 \dots \approx 0

x \approx 2.43400 \dots

The solutions are

x \approx - 0.47088 \dots, x \approx - 1.96312 \dots, x \approx 2.43400 \dots

3 t - t^{3} = 0

4 x^{3} = 8 x

4 x^{3} = 80

x^{3} + 8 = (x + 2)

x^{3} - x^{2} + x = - 5

What are the solutions to the equation 4x^3-20x-9=0 ?
The solutions to the equation 4x^3-20x-9=0 are x\approx-0.47088…,x\approx-1.96312…,x\approx 2.43400…
Find the zeros of 4x^3-20x-9=0
The zeros of 4x^3-20x-9=0 are x\approx-0.47088…,x\approx-1.96312…,x\approx 2.43400…