What are the solutions to the equation 3x^4=27x^2 ?

The solutions to the equation 3x^4=27x^2 are x=0,x=-3,x=3

Find the zeros of 3x^4=27x^2

The zeros of 3x^4=27x^2 are x=0,x=-3,x=3

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3 x^{4} = 27 x^{2}

x = 0, x = - 3, x = 3

Solution steps

3 x^{4} = 27 x^{2}

Move

27 x^{2}

to the left side

3 x^{4} - 27 x^{2} = 0

Factor

3 x^{4} - 27 x^{2} : 3 x^{2} (x + 3) (x - 3)

3 x^{2} (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - 3, x = 3

4 x^{2} + 4 = 3 x^{3} + 3 x

2 (x + 1) - 6 x = 15 x^{21}

x, t = 64 - 6 x^{3}

4 a^{4} + 56 a^{3} + 196 a^{2} = 0

3 x^{3} - 24 x + 36 = 0

What are the solutions to the equation 3x^4=27x^2 ?
The solutions to the equation 3x^4=27x^2 are x=0,x=-3,x=3
Find the zeros of 3x^4=27x^2
The zeros of 3x^4=27x^2 are x=0,x=-3,x=3