What are the solutions to the equation x=-1.3x^3-4x^2-13x-6 ?

The solutions to the equation x=-1.3x^3-4x^2-13x-6 are x\approx-0.48523…

Find the zeros of x=-1.3x^3-4x^2-13x-6

The zeros of x=-1.3x^3-4x^2-13x-6 are x\approx-0.48523…

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x = - 1.3 x^{3} - 4 x^{2} - 13 x - 6

x \approx - 0.48523 \dots

Solution steps

x = - 1.3 x^{3} - 4 x^{2} - 13 x - 6

Multiply both sides by

10

x \cdot 10 = - 13 x^{3} - 40 x^{2} - 130 x - 60

Switch sides

- 13 x^{3} - 40 x^{2} - 130 x - 60 = x \cdot 10

Move

x 10

to the left side

- 13 x^{3} - 40 x^{2} - 140 x - 60 = 0

Find one solution for

- 13 x^{3} - 40 x^{2} - 140 x - 60 = 0

using Newton-Raphson:

x \approx - 0.48523 \dots

Apply long division:

\frac{- 13 x ^{3} - 40 x ^{2} - 140 x - 60}{x + 0.48523 \dots} = - 13 x^{2} - 33.69194 \dots x - 123.65149 \dots

- 13 x^{2} - 33.69194 \dots x - 123.65149 \dots \approx 0

Find one solution for

- 13 x^{2} - 33.69194 \dots x - 123.65149 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 0.48523 \dots

(\frac{1}{5}) x^{5} = 1

8 x^{12} = 6 x + 4

2 x - 712 - 4 - x^{6} = 1920

(7 x + 1) (5 x^{3} - 10 x^{2}) = 0

(x^{2} - 5 x) (x - 36) = 0

What are the solutions to the equation x=-1.3x^3-4x^2-13x-6 ?
The solutions to the equation x=-1.3x^3-4x^2-13x-6 are x\approx-0.48523…
Find the zeros of x=-1.3x^3-4x^2-13x-6
The zeros of x=-1.3x^3-4x^2-13x-6 are x\approx-0.48523…