What are the solutions to the equation (1+x/(12))^{12}=0.12 ?

The solutions to the equation (1+x/(12))^{12}=0.12 are x=-1.94351…,x=-22.05648…

Find the zeros of (1+x/(12))^{12}=0.12

The zeros of (1+x/(12))^{12}=0.12 are x=-1.94351…,x=-22.05648…

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(1 + \frac{x}{12})^{12} = 0.12

x = - 1.94351 \dots, x = - 22.05648 \dots

Solution steps

(1 + \frac{x}{12})^{12} = 0.12

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = - 1.94351 \dots, x = - 22.05648 \dots

m^{3} - 2 m^{2} + m = 0

4 x^{3} - 6 = 0

- 8 x^{3} + 18 x = 0

x^{8} - 20 x^{4} + 64 = 0

- x^{3} + 3 x^{2} + 6 x - 10 = 0

What are the solutions to the equation (1+x/(12))^{12}=0.12 ?
The solutions to the equation (1+x/(12))^{12}=0.12 are x=-1.94351…,x=-22.05648…
Find the zeros of (1+x/(12))^{12}=0.12
The zeros of (1+x/(12))^{12}=0.12 are x=-1.94351…,x=-22.05648…