What are the solutions to the equation x^3-6x^2+2x+24=0 ?

The solutions to the equation x^3-6x^2+2x+24=0 are x=4,x=1+sqrt(7),x=1-sqrt(7)

Find the zeros of x^3-6x^2+2x+24=0

The zeros of x^3-6x^2+2x+24=0 are x=4,x=1+sqrt(7),x=1-sqrt(7)

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x^{3} - 6 x^{2} + 2 x + 24 = 0

x = 4, x = 1 + 7, x = 1 - 7

Decimal Notation

x = 4, x = 3.64575 \dots, x = - 1.64575 \dots

Solution steps

x^{3} - 6 x^{2} + 2 x + 24 = 0

Factor

x^{3} - 6 x^{2} + 2 x + 24 : (x - 4) (x^{2} - 2 x - 6)

(x - 4) (x^{2} - 2 x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x^{2} - 2 x - 6 = 0

Solve

x - 4 = 0 : x = 4

Solve

x^{2} - 2 x - 6 = 0 : x = 1 + 7, x = 1 - 7

The solutions are

x = 4, x = 1 + 7, x = 1 - 7

x^{3} - 4 x^{2} + x = 0

x^{4} - 5 x^{6} = x + 1

1000000 = 100000 (x^{20})

x^{3} = \frac{64}{729}

r^{3} + r^{2} - 2 r = 0

What are the solutions to the equation x^3-6x^2+2x+24=0 ?
The solutions to the equation x^3-6x^2+2x+24=0 are x=4,x=1+sqrt(7),x=1-sqrt(7)
Find the zeros of x^3-6x^2+2x+24=0
The zeros of x^3-6x^2+2x+24=0 are x=4,x=1+sqrt(7),x=1-sqrt(7)