What are the solutions to the equation h^3=1 ?

The solutions to the equation h^3=1 are h=1,h=-1/2+(sqrt(3))/2 i,h=-1/2-(sqrt(3))/2 i

Find the zeros of h^3=1

The zeros of h^3=1 are h=1,h=-1/2+(sqrt(3))/2 i,h=-1/2-(sqrt(3))/2 i

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h^{3} = 1

h = 1, h = - \frac{1}{2} + \frac{3}{2} i, h = - \frac{1}{2} - \frac{3}{2} i

Solution steps

h^{3} = 1

For

x^{3} = f (a)

the solutions are

h = 1, h = \frac{- 1 + 3 i}{2}, h = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

h = 1, h = - \frac{1}{2} + \frac{3}{2} i, h = - \frac{1}{2} - \frac{3}{2} i

x^{3} + 3 x^{2} + x - 3 = 0

0 = 36 x^{3} - 49 x

4 x^{3} + 24 x - x - 6 = 0

(b^{2})^{0} = b^{8}

x^{3} - 4 x + 4 = 0

What are the solutions to the equation h^3=1 ?
The solutions to the equation h^3=1 are h=1,h=-1/2+(sqrt(3))/2 i,h=-1/2-(sqrt(3))/2 i
Find the zeros of h^3=1
The zeros of h^3=1 are h=1,h=-1/2+(sqrt(3))/2 i,h=-1/2-(sqrt(3))/2 i