What are the solutions to the equation r^4+8r^3+7r^2-72r-144=0 ?

The solutions to the equation r^4+8r^3+7r^2-72r-144=0 are r=-3,r=3,r=-4

Find the zeros of r^4+8r^3+7r^2-72r-144=0

The zeros of r^4+8r^3+7r^2-72r-144=0 are r=-3,r=3,r=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{4} + 8 r^{3} + 7 r^{2} - 72 r - 144 = 0

r = - 3, r = 3, r = - 4

Solution steps

r^{4} + 8 r^{3} + 7 r^{2} - 72 r - 144 = 0

Factor

r^{4} + 8 r^{3} + 7 r^{2} - 72 r - 144 : (r + 3) (r - 3) (r + 4)^{2}

(r + 3) (r - 3) (r + 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r + 3 = 0 or r - 3 = 0 or r + 4 = 0

Solve

r + 3 = 0 : r = - 3

Solve

r - 3 = 0 : r = 3

Solve

r + 4 = 0 : r = - 4

The solutions are

r = - 3, r = 3, r = - 4

27 x^{5} + 8 x^{2} = 0

49 - x^{5} = 17

x (x + 5) = (x^{2} + 5 x)^{2}

4 = (1 + \frac{r}{2})^{20}

9 x^{3} - 4 = 0

What are the solutions to the equation r^4+8r^3+7r^2-72r-144=0 ?
The solutions to the equation r^4+8r^3+7r^2-72r-144=0 are r=-3,r=3,r=-4
Find the zeros of r^4+8r^3+7r^2-72r-144=0
The zeros of r^4+8r^3+7r^2-72r-144=0 are r=-3,r=3,r=-4