What are the solutions to the equation y^2y^2-y=6 ?

The solutions to the equation y^2y^2-y=6 are y\approx-1.45972…,y\approx 1.66384…

Find the zeros of y^2y^2-y=6

The zeros of y^2y^2-y=6 are y\approx-1.45972…,y\approx 1.66384…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} y^{2} - y = 6

y \approx - 1.45972 \dots, y \approx 1.66384 \dots

Solution steps

y^{2} y^{2} - y = 6

Refine

y^{4} - y = 6

Move

6

to the left side

y^{4} - y - 6 = 0

Find one solution for

y^{4} - y - 6 = 0

using Newton-Raphson:

y \approx - 1.45972 \dots

Apply long division:

\frac{y ^{4} - y - 6}{y + 1.45972 \dots} = y^{3} - 1.45972 \dots y^{2} + 2.13079 \dots y - 4.11036 \dots

y^{3} - 1.45972 \dots y^{2} + 2.13079 \dots y - 4.11036 \dots \approx 0

Find one solution for

y^{3} - 1.45972 \dots y^{2} + 2.13079 \dots y - 4.11036 \dots = 0

using Newton-Raphson:

y \approx 1.66384 \dots

Apply long division:

\frac{y ^{3} - 1.45972 \dots y ^{2} + 2.13079 \dots y - 4.11036 \dots}{y - 1.66384 \dots} = y^{2} + 0.20411 \dots y + 2.47041 \dots

y^{2} + 0.20411 \dots y + 2.47041 \dots \approx 0

Find one solution for

y^{2} + 0.20411 \dots y + 2.47041 \dots = 0

using Newton-Raphson:

No Solution for

y \in R

The solutions are

y \approx - 1.45972 \dots, y \approx 1.66384 \dots

x^{3} + 5 x^{2} - 2 = 0

x^{3} + 4 x^{2} + 5 x + 1 = 0

x^{3} + 27 + 3 (x + 3) = 0

(x) = 2 x^{3} - 1500

x^{4} - (x - 0.5)^{4} = 1 0^{4}

What are the solutions to the equation y^2y^2-y=6 ?
The solutions to the equation y^2y^2-y=6 are y\approx-1.45972…,y\approx 1.66384…
Find the zeros of y^2y^2-y=6
The zeros of y^2y^2-y=6 are y\approx-1.45972…,y\approx 1.66384…