What are the solutions to the equation 8x^4-8x^3-6x^2=0 ?

The solutions to the equation 8x^4-8x^3-6x^2=0 are x=0,x=-1/2 ,x= 3/2

Find the zeros of 8x^4-8x^3-6x^2=0

The zeros of 8x^4-8x^3-6x^2=0 are x=0,x=-1/2 ,x= 3/2

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8 x^{4} - 8 x^{3} - 6 x^{2} = 0

x = 0, x = - \frac{1}{2}, x = \frac{3}{2}

Decimal Notation

x = 0, x = - 0.5, x = 1.5

Solution steps

8 x^{4} - 8 x^{3} - 6 x^{2} = 0

Factor

8 x^{4} - 8 x^{3} - 6 x^{2} : 2 x^{2} (2 x + 1) (2 x - 3)

2 x^{2} (2 x + 1) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0 or 2 x - 3 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = - \frac{1}{2}, x = \frac{3}{2}

x^{5} - 3 x + 9 = 0

x^{3} - 9 x^{2} + 33 x + 45 = 2

x, x^{3} = 729

(y^{2} - y + 1)^{2} = 0

x^{3} + 2 x + 1 x = 3

What are the solutions to the equation 8x^4-8x^3-6x^2=0 ?
The solutions to the equation 8x^4-8x^3-6x^2=0 are x=0,x=-1/2 ,x= 3/2
Find the zeros of 8x^4-8x^3-6x^2=0
The zeros of 8x^4-8x^3-6x^2=0 are x=0,x=-1/2 ,x= 3/2