What are the solutions to the equation 25x^4-26x^2+1=0 ?

The solutions to the equation 25x^4-26x^2+1=0 are x=1,x=-1,x= 1/5 ,x=-1/5

Find the zeros of 25x^4-26x^2+1=0

The zeros of 25x^4-26x^2+1=0 are x=1,x=-1,x= 1/5 ,x=-1/5

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25 x^{4} - 26 x^{2} + 1 = 0

x = 1, x = - 1, x = \frac{1}{5}, x = - \frac{1}{5}

Decimal Notation

x = 1, x = - 1, x = 0.2, x = - 0.2

Solution steps

25 x^{4} - 26 x^{2} + 1 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

25 u^{2} - 26 u + 1 = 0

Solve

25 u^{2} - 26 u + 1 = 0 : u = 1, u = \frac{1}{25}

u = 1, u = \frac{1}{25}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = \frac{1}{25} : x = \frac{1}{5}, x = - \frac{1}{5}

The solutions are

x = 1, x = - 1, x = \frac{1}{5}, x = - \frac{1}{5}

x^{3} - 3 x^{2} - 33 x + 35 = 0

8 = u^{3}

t^{5} (3 t + 6) = 4 (80 - 2 t)

2 x^{2} (x - 3) = 0

5 - x^{3} = 0

What are the solutions to the equation 25x^4-26x^2+1=0 ?
The solutions to the equation 25x^4-26x^2+1=0 are x=1,x=-1,x= 1/5 ,x=-1/5
Find the zeros of 25x^4-26x^2+1=0
The zeros of 25x^4-26x^2+1=0 are x=1,x=-1,x= 1/5 ,x=-1/5