What are the solutions to the equation x^4-3x^3+3x^2-x=0 ?

The solutions to the equation x^4-3x^3+3x^2-x=0 are x=0,x=1

Find the zeros of x^4-3x^3+3x^2-x=0

The zeros of x^4-3x^3+3x^2-x=0 are x=0,x=1

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x^{4} - 3 x^{3} + 3 x^{2} - x = 0

x = 0, x = 1

Solution steps

x^{4} - 3 x^{3} + 3 x^{2} - x = 0

Factor

x^{4} - 3 x^{3} + 3 x^{2} - x : x (x - 1)^{3}

x (x - 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = 1

x^{3} - 27 x = - 10

x^{3} - 13 x^{2} + 56 x - 80 = 0

(t)^{3} = 1.55

9 m^{5} = 27 m^{3}

x^{3} - 4 x^{2} - 8 x - 10 = 0

What are the solutions to the equation x^4-3x^3+3x^2-x=0 ?
The solutions to the equation x^4-3x^3+3x^2-x=0 are x=0,x=1
Find the zeros of x^4-3x^3+3x^2-x=0
The zeros of x^4-3x^3+3x^2-x=0 are x=0,x=1