What are the solutions to the equation 0=x^2+6x-16 ?

The solutions to the equation 0=x^2+6x-16 are x=2,x=-8

Find the zeros of 0=x^2+6x-16

The zeros of 0=x^2+6x-16 are x=2,x=-8

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0 = x^{2} + 6 x - 16

x = 2, x = - 8

Solution steps

0 = x^{2} + 6 x - 16

Switch sides

x^{2} + 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 \cdot 1}, x_{2} = \frac{- 6 - 10}{2 \cdot 1}

x = \frac{- 6 + 10}{2 \cdot 1} : 2

x = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

16 x - x^{2} - 48

- yz (3 - 10)

\frac{x}{6} - 2 = 13

5 (2 - 3 x) > 3 (2 - 3 x)

780 e^{- \frac{10}{65}} + 780

What are the solutions to the equation 0=x^2+6x-16 ?
The solutions to the equation 0=x^2+6x-16 are x=2,x=-8
Find the zeros of 0=x^2+6x-16
The zeros of 0=x^2+6x-16 are x=2,x=-8