What are the solutions to the equation x^3-9x^3=8 ?

The solutions to the equation x^3-9x^3=8 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i

Find the zeros of x^3-9x^3=8

The zeros of x^3-9x^3=8 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i

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x^{3} - 9 x^{3} = 8

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

Solution steps

x^{3} - 9 x^{3} = 8

Add similar elements:

x^{3} - 9 x^{3} = - 8 x^{3}

- 8 x^{3} = 8

Divide both sides by

- 8

x^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

x = - 1, x = \frac{1}{2} - \frac{3}{2} i, x = \frac{1}{2} + \frac{3}{2} i

2 x^{3} + 3 x^{2} - 18 x = 27

- 12 x^{4} - 27 x^{3} = 0

14 n^{3} - 2 n^{2} = 0

2 x^{5} - 3 x^{4} - 7 x^{2} + 5 = 0

2 x^{4} + x^{3} - 29 x^{2} - 34 x = 24

What are the solutions to the equation x^3-9x^3=8 ?
The solutions to the equation x^3-9x^3=8 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i
Find the zeros of x^3-9x^3=8
The zeros of x^3-9x^3=8 are x=-1,x= 1/2-(sqrt(3))/2 i,x= 1/2+(sqrt(3))/2 i